Question

Find the x-intercepts of the equation shown below. Round to the nearest tenth.
y=0.3(x)^2 + 1.8 (x) - 2

Answer 1

\[y= 0.3 x ^{2} + 1.8 x -2\]

Answer 2

The x intercepts are where the Y-Value=0. Plug in 0 for Y.

Answer 3

Then, divide the whole equation by 0.3.

Answer 4

Then, if you can't see the answer, use \[x=\frac{(-b \pm \sqrt{_{b^{2}}-4ac}) }{ 2a }\]

Answer 5

I got -7.0 and 1.0 rounded to the nearest tenth
thank you so much

Answer 6

No problem.