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OpenStudy (anonymous):
Calculate the integral. dz/z^2+36 from neg infinity to infinity. I got the the integral (1/6arctan(z/6)) and tried to solve it going from 0 to infinity but I just end up with 0. Am i missing something?
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OpenStudy (anonymous):
\[\int\limits_{-\infty}^{\infty} dz/z^2+36\]
OpenStudy (anonymous):
nevermind, i figured it out. :>
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