Which of these is the correct way to rewrite this as a logarithm?

x2 = 169

A)log2x = 169
B)logx169 = 2
C)log2169 = x
D)logx2 = 169

I did this one myself but I am not too sure it is correct? Some help? :)

Question

Which of these is the correct way to rewrite this as a logarithm?

x2 = 169

A)log2x = 169
B)logx169 = 2
C)log2169 = x
D)logx2 = 169

I did this one myself but I am not too sure it is correct? Some help? :)

ankit042 · Answer

is it x^2? as in x raised to power 2

anonymous · Answer

Oh yes I am sorry it didn't look like that when I typed it

jim_thompson5910 · Answer

what answer did you get cayssaday ?

anonymous · Answer

My answer was A

jim_thompson5910 · Answer

keep in mind that 

$$\Large b^x = y$$

converts to 

$$\Large \log_{b}(y) = x$$

(or vice versa)

jim_thompson5910 · Answer

so for example,

$$\Large 3^m = 10$$

turns into

$$\Large \log_{3}(10) = m$$

anonymous · Answer

Ohhhh okay that makes perfect sense thank you so much

jim_thompson5910 · Answer

you're welcome