Question

Hey! Thanks for any help... Which method is correct?... :) (below in comments)

Answer 1

\[2^{4x}-7\times2^{3x} = 0\]
\[-7 \times 2^{3x} = -2^{4x}\]
\[-7 = -2^{4x}\div2^{3x}\]
\[-7 = -2^{x}\]

Answer 2

or...
\[2^{4x}-7\times2^{3x}=0\]
\[2^{3x}(2^{x}-7)=0\]
\[2^{x}-7=0\div2^{3x}\]
\[2^{x}-7 = 0\]
\[2^{x}= 7\]

Answer 3

It's the same thing.

Answer 4

Nonetheless, the second method is preferred.

Answer 5

great thanks! Yeah I knew they were the same just didn't know which method was preferred. :-)