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Physics 13 Online
OpenStudy (anonymous):

Under what condition is |A⃗ − B⃗ |=A+B?

OpenStudy (anonymous):

ok i think you know |A⃗ − B⃗ | is magnitude of A⃗ − B⃗ so \[ |A⃗ − B⃗ |=\sqrt{A^2 + B^2 - 2AB \cos \theta} \] now put \[\theta = \pi\] you will get it.

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