Question

under which condition is ax^2+bx+c wher a=1 factorable

Answer 1

If you are working with complex numbers, you can always factor it.

If you are working with real numbers, the condition is that you can solve for x.

Answer 2

\[\Delta\ge0\](\(\Delta=b^2-4ac\))

Answer 3

Maybe I was a little unclear. The condition is that you can solve (you expression) = 0 for x.