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Identify the vertical asymptotes of f(x) = quantity x plus 6 over quantity x squared minus 9x plus 18 Answer chices are x = -6 and x = -3 x = -6 and x = 3 x = 6 and x = -3 x = 6 and x = 3
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Vertical asymptotes occur when the denominator equals 0. Can you factor x^2 - 9x + 18 and solve for x when the denominator equals 0?
so (X-3)(X-6)..now what? @iPwnBunnies
Set both factors = 0 and solve for x. The vertical asymptotes will occur at x = _ & _
oh nvm..i get it now thx a lot
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