Question

Ho do i find dy/dx if y=e^x sin 2x

Answer 1

taking loge both sides we get,
->lny=xsin2x
differentiating both sides with respect to x we get,
-> \[\frac{ 1 }{ y }\frac{ dy }{dx }=2xcos2x + \sin2x\]\[\frac{ dy }{ dx }= y (2xcos2x +\sin2x)\]\[\frac{ dy }{ dx }= e ^{xsin2x}(2xcos2x +\sin2x)\] please comment if some step is wrong