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x+y=12 x-y=4
Let the numbers be x and y therefore x+y= 12 and x-y=4 adding the two equations we have x+y + x-y= 12+4 2x= 16 x= 8 substituting x= 8 in x+y= 12 we find x+y= 12 y=12-8 y= 4 hence x= 8 and y= 4 are the required numbers..
verification 8+4= 12 and 8-4 = 4
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