Question

help

Answer 1

hmm
assuming regular seats =x
sleeper seats=y
128x+284y=20100
x+y=90

solve ;)

Answer 2

(35,55)

Answer 3

bingo (y)

Answer 4

Let x passengers purchased of regular class and y passenger pur of sleeper coach.
hence
total number of psons
x+y= 90
i.e. x= 90-y ----(1
and money
128 x + 284 y= 20,100 ----(2
Substituting x= 90-y in eq (2 we find:
128 (90-y) + 284 y= 20,100

11520 -128 y + 284 y = 20, 100
156 y= 20,100- 11520=8580
i.e. y= 8580/156 =55
i.e. y= 55
Substituting y= 55 in eq (1 we find
x= 90-y = 90- 55 = 35
i.e. x= 35
Hence
35 passengers purchased of regular class
and
55 passenger purchase of sleeper coach tickets.

@vshiroky