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OpenStudy (anonymous):
the equation of the line tangent to y=2secx at ax=pi/4 is ? and i get 2sqr2x-y=squr2/2pi-2sqt2, am i correct??
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hartnn (hartnn):
you mean this ? \(2\sqrt 2x -y = (\sqrt 2/2)\pi - 2\sqrt 2\) then yes, its correct :)
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