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OpenStudy (anonymous):
Please help. Solve for x for [0.2pi] 2cosxsinx - cosx=0
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OpenStudy (anonymous):
cosx(2sinx-1)=0 cosx=0 when x= pi/2 or 3pi/2 2sinx-1=0 2sinx=1 sinx=.5 when x= pi/6 or x= 5pi/6 Answer is pi/2, 3pi/2, pi/6, 5pi/6
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