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solve each system by substitution y=-4x-12 y=-3x-10
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\[-4x-12=-3x-10\] solve for \(x\)
add \(4x\) to both sides to get \[-12=x-10\] then add \(10\) to get \[-2=x\]
if \(x=-2\) then \(y=-4(-2)-12=8-12=-4\) so your answer is \((-2,-4)\)
thanks that helped alot
yw
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