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Mathematics 14 Online
OpenStudy (lexipoo1998):

Please help. Medal! Write the general form of the equation which matches the graph below.In complete sentences, explain the process taken to find this equation.

OpenStudy (lexipoo1998):

OpenStudy (lexipoo1998):

@robtobey @radar @precal @hoblos can any of you help?

OpenStudy (lexipoo1998):

By chance is this right?

OpenStudy (lexipoo1998):

(y-3)^2 = -16x

OpenStudy (lexipoo1998):

@AccessDenied @bakonloverk @Compassionate @Diego98512 @eliassaab @Firejay5 Can any of you help?

OpenStudy (anonymous):

Your answer is correct.

OpenStudy (lexipoo1998):

How do I explain it though? By chance can you help me give an explanation? @eliassaab

OpenStudy (anonymous):

Let (x,y) be a point on the parabola, then the distance from (x,y) to the focus must be equal to the distance to the directrix x=4, Hence \[ (x+4)^2+(y-3)^2=(x-4)^2\\ (y-3)^2=(x-4)^2-(x+4)^2 \\ (y-3)^2=x^2 -8x +16 - x^2 -8x -16=-16 x \]

OpenStudy (lexipoo1998):

Thank you

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