Question

[7.08] Find the quotient of quantity of 24 times x to the 2nd power times y plus 12 times x times y to the 3rd power minus 18 times x times y all over 6 times x times y.
Select one:
a. 6y2 − 18
b. 4x + 2y2 − 3
c. 12x2 − 18x + 3
d. x3y2 + 2x2y4 − 4x2y2

Answer 1

\[\large \frac{24x^2y + 12xy^3 - 18xy}{6xy} = \frac{24x^2y}{6xy} + \frac{12xy^3}{6xy} - \frac{18xy}{6xy} = \space ?\]

Answer 2

I'm not sure, d?

Answer 3

Lets do it by parts...

\[\large \frac{24x^2y}{6xy} = \frac{24}{6} \times \frac{x^2}{x} \times \frac{y}{y} = 4 \times x \times 1 = 4x\]

Thats the first part...can you do the rest?