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Physics 11 Online
OpenStudy (anonymous):

A electron travelling at 5.0*10^5 m/s enters through a hole in a positive plate and collides with the negative plate at 1.0*10^5 m/s. Determine the electrical potential differnece between the charger plates

OpenStudy (anonymous):

\[\frac{ 1 }{ 2 } mv^2 _{2}- \frac{ 1 }{ 2 } mv^2 _{1} = eV\] m and e are mass and charge of the electron

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