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Mathematics 10 Online
OpenStudy (anonymous):

Hello. Please help me with part (b)... WILL GIVE MEDALS. http://postimg.org/image/qm02zn35z/

OpenStudy (anonymous):

t[n]=(2n+(1+n)/10)^2 to find the sum, expand & use telescoping series

OpenStudy (anonymous):

\[\sum_{1}^{n}(2n)+\sum_{1}^{n}(n+1)(n+1)\]

OpenStudy (anonymous):

actually, the formula for sum(n^2) is given

OpenStudy (anonymous):

but it is also valid for (n+1)^2

OpenStudy (anonymous):

t[n] = (2n+(1+n)/10)^2 = .01 + .42n + 4.41n^2

OpenStudy (anonymous):

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