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Find the volume of the solid generated by revolving the region bounded by y=3(x)^(1/2) and the lines y=6 and x=0 about x=4. When using the shell method why is the h, 3(x)^(1/2)-6 instead of 6-3(x)^(1/2)? Is the h the height of the region thats above x=4?
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