Question

Plz help?

Answer 1

Area of the figure = area of the rectangle + area of the semicircle
\[\huge = lb + \pi r^2 = 3 \times 8 +\frac{1}{2} \times 3.14 \times 4^2\]
\[\huge = 24 + 3.14 \times 16= 24+25.12=49.12]
Hence are of the given figure is 49.12 sq units...

Answer 2

Here if the pic.