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HELP: Solve: 35q^2+33q+4=0
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@dpasingh
you need to check out factors of 35 and + 4 and figure out how you can get middle coefficient +33 35 = 5 * 7 4 = 4 * 1 28 + 5 = 33 thats it
7*4 + 5*1
giving (5q+ 4 )(7q + 1 )
(5q + 4)(7q + 1) = 0
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\[\huge 35q^2+33q+4=0\] \[\huge 35q^2+28q + 5q+4=0\] \[\huge 7q(5q+4) +1( 5q+4)=0\] \[\huge (7q +1)( 5q+4)=0\] (7q +1)=0 or ( 5q+4)=0 q= -1/7 , -4/5
thank you both.
yw the middle coefficient is obtained as in diagram |dw:1395079404591:dw|
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