Help please A model rocket is launched from a roof into a large field. The path of the rocket can be molded by the equation y= -0.04x^2 + 8.3x + 4.3, where x is the horizontal distance, in meters, from starting point on the roof and y is the distance in the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round to the nearest hundredth meter.
A.) 208.02m B.) 416.03m C.) 0.52m D.) 208.19m
hmm cool question! a medal for that at first!!!!
then the solution:
sure if u can help me figure this out
okay: suppose the rocket is launched from (0,0) in a coordinate axis. so when it lands its y coordinate is 0. so put y=0 in the eqn of trajectory and solve for x. QUADRATIC EQUATION IT IS. :D
so im supposed to use the quadratic equation for this?
YUP
okay thanks :D i got it from here
:D
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