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the length of a rectangle is 2 more than the width. the area is 80 feet. find the dimensions
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L+W2=80
how would you solv it?
first divide w2 by 2 then 80 by 4 =40 which then leaves you with L=40 You just have to balance the equation
whoops 80 by 2 i meant
those arent my answers though. I have A) L=10,W=8 B)L=20, W=4 C) L=12, W10 the answer is A
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oh whoops must have slipped up on that one.
yea im havin a hard time with it, any help would be appreciated.
|dw:1395086955556:dw| once you get the width, keep in mind the length is just 2 units more than that :)
thank you, got it now.
yw
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