Question

A rectangle has a width to length ratio of2:5. The perimeter is 322 feet. What is the area enclosed

Answer 1

Let the length be 5x and breadth be 2x
the perimeter is 2(5x+2x)=322
then 7x=161
x=23
the area is 5x*2x=10(x)^2
area=5290 by substituting the value of x in it!!1

Answer 2

If ρ and κ are the two sides of the rectangle then ρ/κ = 2/5 (1)
The perimeter is 2ρ + 2κ = 322 (2)
Now time to solve..
(1) can be written as ρ = 2κ/5 and so from the second one we have 2( 2κ/5 ) + 2κ = 322 and therefore 4κ + 10κ = 322 * 5 and 14κ = 1610 so κ = 115
But remember than ρ/κ = 2/5 ?
So ρ = 2κ/5 meaning ρ = 46
Finally the area is κ * p = 46 * 115 = 5290