Question

if y varies directly as the square of x, and y=925 when x=25 find y whenx=20

Answer 1

Based on the info given , I infer :
y=x^2+c, where c is the constant
925=25^2+c
925=625+c
or c=300
so,
y=(20)^2+300
y=400+300
y=700

Please check if I my answer is right

Answer 2

It is no good. Direct and Inverse variation cannot have such an additive constant.

\(y = k\cdot x^{2}\)

Now, substitute the given values and solve for k.