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Mathematics 54 Online
OpenStudy (anonymous):

Find the value of this two problems: @kc_kennylau

OpenStudy (anonymous):

@kc_kennylau @mathmale

OpenStudy (kc_kennylau):

Encuentra \(\sin\dfrac\pi3\) primero

OpenStudy (anonymous):

Answer 1. arccos(sin 60) arrcos(cos 30) ;as cos (90-x)=sinx 30

OpenStudy (anonymous):

sinπ/3 sería 60°

OpenStudy (kc_kennylau):

Su metodo functiona tambien

OpenStudy (kc_kennylau):

Usamos su metodo

OpenStudy (kc_kennylau):

Convierte \(\sin\dfrac\pi3\) a \(\cos\) primero

OpenStudy (anonymous):

So, the answer is 30°?

OpenStudy (kc_kennylau):

Si

OpenStudy (anonymous):

arcsin 1 = 90 degree arccos 1/2 = 30 degree Their difference 60 degree, so tan 60= \[\sqrt{3}/2\]

OpenStudy (anonymous):

I didn't get the last one! :( @kc_kennylau

OpenStudy (anonymous):

No entendí la última! @kc_kennylau

OpenStudy (kc_kennylau):

La ultima cuestion significas tu?

OpenStudy (kc_kennylau):

tienes la tabla

OpenStudy (kc_kennylau):

sen 90 es 1

OpenStudy (kc_kennylau):

usa la tabla

OpenStudy (anonymous):

Yep! By the way, you don't say ''cuestion'' in Spanish, we say ''pregunta''! The right way to say what you wanted to say in Spanish is: '' Te refieres a la última pregunta?'' Ok, I'll use it!

OpenStudy (kc_kennylau):

gracias por la correccion :)

OpenStudy (anonymous):

No hay de que! back to the homework! I found that sin of 90° is 1 already, what do I have to do now!?! :o

OpenStudy (kc_kennylau):

cos 60 es 1/2 por tu tabla

OpenStudy (anonymous):

Yep! Do I have to add them or what? :o

OpenStudy (kc_kennylau):

Veamos lo que tenemos ahora:

OpenStudy (kc_kennylau):

tan(arcsen 1 - arccos 1/2) = tan(90-60)

OpenStudy (kc_kennylau):

Pienses que lo puedes hacer?

OpenStudy (anonymous):

30°! So it'd be \[\sqrt{3}/3\] ?

OpenStudy (anonymous):

Cómo sacaste eso?/How did you get that? :o

OpenStudy (kc_kennylau):

estas correcta

OpenStudy (kc_kennylau):

disculpe

OpenStudy (anonymous):

Ohhh okay, I see lol, hey, I have to go but, I'll come back in a bit! Can you help me on other 3 problems that I'm having trouble with? please?!? :-)

OpenStudy (kc_kennylau):

sin duda :)

OpenStudy (anonymous):

Muchas gracias! Regreso como en unos 30 minutos. Estarás aquí aún?/ Thank you very much! I'll come back like in 30 minutes. Will you still be here?

OpenStudy (kc_kennylau):

No deberias traducir todos en espanol, y pienso que si :)

OpenStudy (anonymous):

Why not? It is better for you! En un momento regreso!

OpenStudy (kc_kennylau):

de donde vienes tu?

OpenStudy (anonymous):

Hey, I'm back!

OpenStudy (kc_kennylau):

hola

OpenStudy (anonymous):

Hola! :D

OpenStudy (kc_kennylau):

De donde vienes tu? :)

OpenStudy (anonymous):

Te refieres a de donde soy? :o

OpenStudy (kc_kennylau):

si

OpenStudy (anonymous):

México y tu?! :D

OpenStudy (kc_kennylau):

Hong Kong :)

OpenStudy (anonymous):

OMG, ARE YOU SERIOUS?!?! :O

OpenStudy (kc_kennylau):

Si enserio etoy

OpenStudy (anonymous):

That's awesome! :)

OpenStudy (kc_kennylau):

:)

OpenStudy (anonymous):

Hey, could you please help me with another question?! :o

OpenStudy (kc_kennylau):

Como se dice "of course" en epanol :O

OpenStudy (anonymous):

Por supuesto que sí! :D

OpenStudy (anonymous):

Or in the shorter way: ''Por supuesto!'' :)

OpenStudy (kc_kennylau):

Por supueto :D

OpenStudy (anonymous):

Okay, let me post another question and close this one, I'll tag you on the other one!

OpenStudy (kc_kennylau):

vale :)

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