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The slope of the tangent line to the curve y(cos x)+e^y=5 at the point where x=pi/2
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Have you considered calculating dy/dx via the implicit derivative?
how to do that,,,?
product rule and chain rule
\[ y\cos (x)+e^y=5\] \[y'\cos(x)-y\sin(x)+e^yy'=0\] solve for \(y'\)
what do i do with the y when i solve for y'?
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y(cos x)+e^y=5 plug in x=pi/2 and solve that for y. Then plug x=pi/2 and that above y value into the y' equation.
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