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Mathematics 13 Online
OpenStudy (anonymous):

@kc_kennylau publicaré la foto del problema abajo!

OpenStudy (kc_kennylau):

okay :)

OpenStudy (anonymous):

@kc_kennylau look at it :o

OpenStudy (kc_kennylau):

El significado de ete problema es solver la ecuacion: 10 sen ( pi*t/6 - 2*pi/3 ) +57 = 62

OpenStudy (anonymous):

I'm bad with equations! No sé cómo resolverla. Would you like to explain me how to do it? :o

OpenStudy (kc_kennylau):

Convierte todo a grado si te gustaria

OpenStudy (kc_kennylau):

pi/6 = 30 grados 2*pi/3 = 120 grados

OpenStudy (anonymous):

Yeah, and then?! :o

OpenStudy (kc_kennylau):

Saca 57 de los dos lados

OpenStudy (kc_kennylau):

10 sen ( pi*t/6 - 2*pi/3 ) +57 = 62 10 sen ( pi*t/6 - 2*pi/3 ) +57 - 57 = 62 - 57 10 sen ( pi*t/6 - 2*pi/3 ) = 5

OpenStudy (kc_kennylau):

Lo entendiste?

OpenStudy (anonymous):

Absolutely NO! First, how did you get 62? :(

OpenStudy (kc_kennylau):

Porque la temperatura requerida es 62

OpenStudy (anonymous):

ohhh ok, you got it from the problem? xD

OpenStudy (kc_kennylau):

Si :)

OpenStudy (anonymous):

Yeah, I just saw it! Lol, I feel dumb :b

OpenStudy (kc_kennylau):

No no eres :)

OpenStudy (anonymous):

Lol, ok! So.. Is that the answer?!? :O

OpenStudy (kc_kennylau):

Debemos aun lo resolver no?

OpenStudy (anonymous):

I don{t know! What do you think? :o

OpenStudy (kc_kennylau):

10 sen ( pi*t/6 - 2*pi/3 ) +57 = 62 10 sen ( pi*t/6 - 2*pi/3 ) +57 - 57 = 62 - 57 10 sen ( pi*t/6 - 2*pi/3 ) = 5 sen (pi*t/6 - 2*pi/3) = 0.5

OpenStudy (kc_kennylau):

Lo comprendes?

OpenStudy (anonymous):

Nope ._. did you subtract the (pi*t/6 - 2*pi/3) to get 0.5?

OpenStudy (kc_kennylau):

10 sen ( pi*t/6 - 2*pi/3 ) +57 = 62 10 sen ( pi*t/6 - 2*pi/3 ) +57 - 57 = 62 - 57 10 sen ( pi*t/6 - 2*pi/3 ) = 5 10 sen ( pi*t/6 - 2*pi/3 ) / 10 = 5 / 10 sen (pi*t/6 - 2*pi/3) = 0.5

OpenStudy (kc_kennylau):

Ahora lo comprendes?

OpenStudy (anonymous):

ohh! you moved the 10 to the right so you divide 5/10? :o

OpenStudy (kc_kennylau):

Si :)

OpenStudy (kc_kennylau):

Cual es el siguiente paso?

OpenStudy (anonymous):

I think that it is the part that says: ''Which two months is the average temperature 62°?'' Is it?

OpenStudy (kc_kennylau):

Solving equations are like attacking into a castle. You take down the furthest guards first. For example, in the equation 8(3t+4)=56, you remove the 8 first, then the 4, then finally the 3.

OpenStudy (kc_kennylau):

La ecuacion no esta resolvada :)

OpenStudy (kc_kennylau):

Encontrando el "t" estas

OpenStudy (anonymous):

You don't say ''resolvada'' in Spanish, we say ''resolvida'' :D

OpenStudy (anonymous):

I meant ''resuelta''

OpenStudy (kc_kennylau):

oh diculpe :p

OpenStudy (anonymous):

lol c: so, what do we have to do next? :o

OpenStudy (kc_kennylau):

10 sen ( pi*t/6 - 2*pi/3 ) +57 = 62 10 sen ( pi*t/6 - 2*pi/3 ) +57 - 57 = 62 - 57 10 sen ( pi*t/6 - 2*pi/3 ) = 5 10 sen ( pi*t/6 - 2*pi/3 ) / 10 = 5 / 10 sen (pi*t/6 - 2*pi/3) = 0.5 Cual puede "pi*t/6 - 2*pi/3" estar?

OpenStudy (anonymous):

Whaaaaaaat? I don't get it!!! :(

OpenStudy (kc_kennylau):

Si el seno de algo es 0.5, "algo" estaria cual?

OpenStudy (anonymous):

Nope, I still don't get it :/

OpenStudy (kc_kennylau):

sen(algo)=0.5 algo=?

OpenStudy (anonymous):

30°? AY NO! NO LO ENTIENDO! :O

OpenStudy (kc_kennylau):

Si!!! Si!!!

OpenStudy (anonymous):

YAY!! :D

OpenStudy (kc_kennylau):

Y te introduzco una nueva formula: \(\mbox{sen}(x)=\mbox{sen}(\pi-x)\)

OpenStudy (kc_kennylau):

O in grados: \(\mbox{sen}(x)=\mbox{sen}(180^\circ-x)\)

OpenStudy (kc_kennylau):

Pero eta ecuacion no es en grados

OpenStudy (anonymous):

Nope, it is in radians!

OpenStudy (kc_kennylau):

Entonces la formula es \(\mbox{sen}(x)=\mbox{sen}(\pi-x)\)

OpenStudy (kc_kennylau):

Que estaria "algo" aparte de 30 grados (o \(\dfrac\pi6\))?

OpenStudy (anonymous):

I really don't know :o could you please tell me? :o

OpenStudy (kc_kennylau):

Porque \(\mbox{sen}30^\circ=\mbox{sen}150^\circ\), algo estaria tambien \(150^\circ\), o en radian \(\frac{5\pi}6\)

OpenStudy (anonymous):

Hmm. So, what do we have to do next? :o

OpenStudy (kc_kennylau):

10 sen ( pi*t/6 - 2*pi/3 ) +57 = 62 10 sen ( pi*t/6 - 2*pi/3 ) +57 - 57 = 62 - 57 10 sen ( pi*t/6 - 2*pi/3 ) = 5 10 sen ( pi*t/6 - 2*pi/3 ) / 10 = 5 / 10 sen (pi*t/6 - 2*pi/3) = 0.5 pi*t/6 - 2*pi/3 = pi/6 \(\mbox o\) pi*t/6 - 2*pi/3 = 5*pi/6

OpenStudy (kc_kennylau):

Continua a resolver eta ecuacione :)

OpenStudy (anonymous):

omg, this is so hard!

OpenStudy (kc_kennylau):

Solve the two equations one by one

OpenStudy (kc_kennylau):

La primera ecuacion: pi*t/6 - 2*pi/3 = pi/6

OpenStudy (kc_kennylau):

Resolve eta ecuacion primero

OpenStudy (kc_kennylau):

Suma lo do lado por 2*pi/3

OpenStudy (anonymous):

5pi/6 ?

OpenStudy (kc_kennylau):

Que te refieras?

OpenStudy (anonymous):

bah, i don't get this! :(

OpenStudy (kc_kennylau):

pi*t/6 - 2*pi/3 = pi/6 pi*t/6 - 2*pi/3 + 2*pi/3 = pi/6 + 2*pi/3

OpenStudy (kc_kennylau):

Complea el tercero paso

OpenStudy (anonymous):

what's the 3rd step?

OpenStudy (kc_kennylau):

Me refiero "escribe el tercero paso" diculpe

OpenStudy (anonymous):

I don't know how to do the next step! :(

OpenStudy (kc_kennylau):

Que es "pi/6 + 2*pi/3"?

OpenStudy (anonymous):

Is it 5pi/6 ?

OpenStudy (kc_kennylau):

Si :)

OpenStudy (kc_kennylau):

En que se convertiria la ecuacion?

OpenStudy (anonymous):

Yayyyyyyyy!

OpenStudy (kc_kennylau):

Escribe el 3o paso?

OpenStudy (anonymous):

hmm, i don't know! lol

OpenStudy (kc_kennylau):

...

OpenStudy (anonymous):

?!?!? :o

OpenStudy (kc_kennylau):

In French I'd say "J'en ai marré" but I don't know how I'd say it in Spanish

OpenStudy (kc_kennylau):

pi*t/6 - 2*pi/3 = pi/6 pi*t/6 - 2*pi/3 + 2*pi/3 = pi/6 + 2*pi/3 pi*t/6 = 5*pi/6

OpenStudy (kc_kennylau):

Puedes encontrar t ahora?

OpenStudy (anonymous):

do i have to divide or something ? :o

OpenStudy (kc_kennylau):

Si

OpenStudy (kc_kennylau):

Multiplica lo do lado por 6

OpenStudy (anonymous):

do i have to divide: pi*t/6 = 5*pi/6 ?

OpenStudy (kc_kennylau):

Entonces divide lo do lado por pi

OpenStudy (kc_kennylau):

Si

OpenStudy (anonymous):

what if i don't have a calculator?!?! D:

OpenStudy (kc_kennylau):

...

OpenStudy (kc_kennylau):

pi*t/6 - 2*pi/3 = pi/6 pi*t/6 - 2*pi/3 + 2*pi/3 = pi/6 + 2*pi/3 pi*t/6 = 5*pi/6 pi*t = 5*pi t = 5

OpenStudy (kc_kennylau):

No nececitas un calculador

OpenStudy (anonymous):

OHH! I just had to leave the 5 alone? :O

OpenStudy (kc_kennylau):

una calculadora*

OpenStudy (kc_kennylau):

Si

OpenStudy (anonymous):

WOW! are we done?!?!?! :O

OpenStudy (kc_kennylau):

No

OpenStudy (kc_kennylau):

Porque hay 2 repueta

OpenStudy (anonymous):

which one? :o

OpenStudy (kc_kennylau):

Has resuelta solo la 1a ecuacion, te acuerdas que hay 2 ecuacione?

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