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Quick question? Find a ⋅ b. a = 8i + 6j, b = 4i + 5j
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Do the ones with the letters look like this: <32, 30>, or this: 62?
@surjithayer
a.b is a scalar quantity. a.b=(8i+6j)(4i+5j)=(8)(4)+(6)(5)=32+30=62
Awesome. Thanks. :D
i.i=i^2=1 i.j=0
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I thought i^2 was -1? Or is that only Algebra?
i and j are unit vectors. \[i.i=\left| i \right|\left| i \right|\cos 0=(1)(1)(1)=1\]
that is iota
iota?
(iota)^2=-1
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Ohhh. That's the real name of that thing.
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