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Mathematics 13 Online
OpenStudy (anonymous):

integral -ycos(y^2) dy

ganeshie8 (ganeshie8):

sub \(u = y^2\)

OpenStudy (anonymous):

du/dy = 2y so dy = du/2y

OpenStudy (anonymous):

becomes integral -cos(u) du/2

OpenStudy (anonymous):

so -1/2sin(y^2) ?

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