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Solve the equation using the quadratic formula. 2x2 = -12x - 3. plz help
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start by moving everything to left side
\(2x^2 = -12x -3\)
\(2x^2 + 12x +3 = 0\)
compare it wid standard quadratic equation : \(\large ax^2 + bx+c = 0\)
\(a = 2\) \(b = 12\) \(c = 3\)
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plug them in quadratic formula : \(\large x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\)
\(\large x = \frac{-12 \pm \sqrt{12^2-4(2)(3)}}{2(2)}\)
simplify
ok thanks
np :)
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:)
2x2 = -12x - 3 2x2 = 4 -12 ÷ 4 = -3
x=12(−6+30−−√),−12(6+30−−√)
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