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Mathematics 15 Online
OpenStudy (anonymous):

evaluate the series 72+12+2+....

OpenStudy (amistre64):

hmmm, 6 might play a role here

OpenStudy (amistre64):

\[A_n=76(\frac{1}{6})^{n-1}\]

Parth (parthkohli):

And the formula for an infinite geometric series is...\[S = \dfrac{a}{1 -r}\]

Parth (parthkohli):

Of course, this is only valid when \(|r|< 1 \), otherwise the series doesn't converge.

OpenStudy (amistre64):

... 72, not 76 but other than that its perfect lol

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