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cos(1/(3x))=0
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\[\cos \left( \frac{ 1 }{3x } \right)=0=\cos n \pi,n \in I,\frac{ 1 }{3x }=n \pi,x=?\]
still lost...
what degree does the input equals to 0 (from 0 to 360) --> 90 and 270 for \[\frac{ 1 }{ 3x } = 90^{o}\] the input of x must be... (same ways for the 270) (the range of this answer is \[0\le x \le360\] ) to be honest, I'm not quite sure about this one. But I think it's like that Sorry if it's not right ):
Its okay thank you for trying :)
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