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Trigonometry
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simplify the formula: y=sinx^4-cox^4
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\[a^4-b^4=(a^2+b^2)(a^2-b^2)\] is a start
then since \(\sin^2(x)+\cos^2(x)=1\) you will get \[\sin^2(x)-\cos^2(x)\]
and doesnt sin2(x)−cos2(x) equal cos2theta?
sin^2 x - cos ^2 x = -cos 2x
thank you!
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