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Mathematics 21 Online
OpenStudy (anonymous):

x +3 = (x - 5)^2

OpenStudy (jdoe0001):

\(\bf x +3 = (x - 5)^2\implies x +3 = (x - 5)(x - 5) \\ \quad \\ x +3 =x^2-5x-5x+25\implies 0=-x -3+x^2-5x-5x+25 \) add like terms and solve for "x" like you'd any quadratics you've already done

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