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Mathematics 20 Online
OpenStudy (anonymous):

help ?????????????????

OpenStudy (anonymous):

5. In the two similar trapezoids below, HE = 20, what is DA?

OpenStudy (anonymous):

10 20 30 40

OpenStudy (anonymous):

please help :(

OpenStudy (anonymous):

@ankit042 @lucaz @NoelGreco @Falco276 @ZainabKhan @Xmoses1 @ybarrap @Skyz @linn99123 @LilliBelle @vetdoc @secret66

OpenStudy (anonymous):

@Mr.ClayLordMath @AccessDenied @Preetha @secret66 @,k @amistre64 @Saeeddiscover

OpenStudy (ankit042):

56/42x = 10x/30 solve for x

OpenStudy (ankit042):

then HE/AD = 10x/30

OpenStudy (ankit042):

@armine can you complete now?

OpenStudy (anonymous):

to be honest no :(

OpenStudy (anonymous):

@ankit042

OpenStudy (ankit042):

lol where are you stuck? can you tell me the value of x?

OpenStudy (anonymous):

can you just start from the beginning like with steps

OpenStudy (anonymous):

@ankit042

OpenStudy (radar):

Step 1. We are dealing with similar figures. But we first must solve for x. Why solve for x? Because some of the needed ratios have the value x in. Step 2. Solve for x Fina a pair of ratios that will allow you to solve for x. Procedure : (10x)/30 = 56/(42x) |dw:1395171535522:dw| Did you follow so far? Answer please.

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