Question

Write the equation for the horizontal line that contains point G(-8,8). (1 point) I need help and explanation!
a. y=-8
b. x=8
c. y=1x + 8
d. y=8

Answer 1

Can you help me?

Answer 2

d. \[ y = 8 \]

Answer 3

Are you in connexus because I need more help?

Answer 4

see the line is horizontal. any line parallel to x axis have the following equation.

y = c ; put (-8, 8) in the equation and you get y = 8

Answer 5

No i am not in connexus. can you tell me what is connexus.

Answer 6

Nvm. But I do get it now.

Answer 7

how it can be helpful to me. I am teacher.

Answer 8

Well can you explain buch more?

Answer 9

about what ?

Answer 10

Hold on Ill type it.

Answer 11

Write the equation for the vertical line that passes through the point (1,-1).
a. x=1
b. x= -y
c. y=-1
d. y=1x

Answer 12

Do you no how to do that?

Answer 13

yup. see it is vertical line. any vertical line has equation of the form x = c, x is constant for any vertical line. so the line is x = 1.

Answer 14

Oh so because of how x is constant!

Answer 15

do you have graph paper? plot these points on the graph and tell me how it looks. (1, 2) (1, 3) (1, 4) (1,5) ( 1,6) ( 1,7) and (1,8)

Answer 16

What is am equation for the line that passes through points (-1,-4) and (1,4)? Write the equation in slope intercept form.
a. y=4x
b. y=-4x
c. y= -1x -4
d. y= -4x + 1 .... Also no I don't have graph paper!

Answer 17

a

y=4x