Question

Radicals and stuff Please help last 2 questions !

Answer 1

\[\sqrt[4]{9}\sqrt{9}/\sqrt[4]{9^5}\]

Answer 2

\(\Large \bf \cfrac{\sqrt[4]{9}\sqrt{9}}{\sqrt[4]{9^5}}\quad ?\)

Answer 3

Yes thats it

Answer 4

@jdoe0001 can you help ? What you did there was the question I need help with solving

Answer 5

ahemmm one sec

Answer 6

Okay Thanks you

Answer 7

\(\large {\bf \sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}\qquad \qquad a^{-\frac{{\color{blue} n}}{{\color{red} m}}} =
\cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}} \implies \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}}
\\ \quad \\ \quad \\

\cfrac{\sqrt[4]{9}\sqrt{9}}{\sqrt[4]{9^5}}\implies\cfrac{\sqrt[4]{9}\sqrt{9^1}}{\sqrt[4]{9^5}}\implies
\cfrac{9^{\frac{1}{4}}\cdot 9^{\frac{1}{2}}}
{9^{\frac{1}{5}}}\implies
\cfrac{9^{\frac{1}{4}}\cdot 9^{\frac{1}{2}}}{1}\cdot \cfrac{1}{9^{\frac{1}{5}}}
\\ \quad \\
\cfrac{9^{\frac{1}{4}}\cdot 9^{\frac{1}{2}}}{1}\cdot 9^{-\frac{1}{5}} }\)

so.. what do you think?

Answer 8

recall your exponent rules -> http://www.math-play.com/image-exponents-rules.jpg <-- notice the 1st rule listed there

Answer 9

hmmm shoot.. I just notice... the denominator has an exponent of 5....lemme fix that quick ahem so
\(\large {\bf \sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}\qquad \qquad a^{-\frac{{\color{blue} n}}{{\color{red} m}}} =
\cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}} \implies \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}}
\\ \quad \\ \quad \\

\cfrac{\sqrt[4]{9}\sqrt{9}}{\sqrt[4]{9^5}}\implies\cfrac{\sqrt[4]{9}\sqrt{9^1}}{\sqrt[4]{9^5}}\implies
\cfrac{9^{\frac{1}{4}}\cdot 9^{\frac{1}{2}}}
{9^{\frac{5}{4}}}\implies
\cfrac{9^{\frac{1}{4}}\cdot 9^{\frac{1}{2}}}{1}\cdot \cfrac{1}{9^{\frac{5}{4}}}
\\ \quad \\
\cfrac{9^{\frac{1}{4}}\cdot 9^{\frac{1}{2}}}{1}\cdot 9^{-\frac{5}{4}} }\)