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Determine the intervals on which the function is concave up and intervals on which the function is concave down. 1. f(x) = x^3. 2. f(x) = x e^(-x). 3.f(x) = x-2 sin x defined on the interval (0,3 pi). 4. f(x) = [x^2]/[x^2-1].
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try to use the second derivitive (\[d^2y/dx^2\]
Then what?
then make it equals zero and then find the values of (X) and after testing them on the numbers scale you can find the concavity or the cancavity
try it if it was hard i`ll explain how to do it
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