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Mathematics 11 Online
OpenStudy (anonymous):

Determine the intervals on which the function is concave up and intervals on which the function is concave down. 1. f(x) = x^3. 2. f(x) = x e^(-x). 3.f(x) = x-2 sin x defined on the interval (0,3 pi). 4. f(x) = [x^2]/[x^2-1].

OpenStudy (anonymous):

try to use the second derivitive (\[d^2y/dx^2\]

OpenStudy (anonymous):

Then what?

OpenStudy (anonymous):

then make it equals zero and then find the values of (X) and after testing them on the numbers scale you can find the concavity or the cancavity

OpenStudy (anonymous):

try it if it was hard i`ll explain how to do it

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