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In a mixture of concrete there are four lb of cement for each pound of gravel. If the mixture contains a total of 95 ib of these two ingrediants, how many pounds of gravel are there?
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\(4\) pounds of cement is there for every \(1\) pound of gravel
that means in every \(5\) pounds of mixture, there is \(1\) pound of gravel right ?
yes
so, in a \(95\) pound mixture, how many pounds of "gravel" will be there ?
simply divide \(5\)
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gravel present in 95 pound mixture = \(\large \frac{95}{5} = 19 \)
see if that makes more or less sense.. .
yes it does thanks
np :)
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