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Mathematics 22 Online
OpenStudy (anonymous):

1/1-sinx = 1+sinx/ cos^2x

OpenStudy (fibonaccichick666):

but yet again there is a type o

OpenStudy (fibonaccichick666):

so the steps you showed me, let's just work with the right side

OpenStudy (fibonaccichick666):

\[1+sin x=?\] \[cos^2x=?\]

OpenStudy (anonymous):

cos^2x = 1-sin^2x

OpenStudy (fibonaccichick666):

and the other?

OpenStudy (fibonaccichick666):

oh wait, wait

OpenStudy (fibonaccichick666):

maybe not a type o on this one let me see

OpenStudy (fibonaccichick666):

k this one is doable

OpenStudy (anonymous):

I thought we could cross out sinx/sinx :(

OpenStudy (fibonaccichick666):

no, that's not how the algebra works

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