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3x+6y=-6 -5x-2y=-14 solve system of equation elimination
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i got -3 as x
multiply first equation with 5, it becomes \[15x+30y=-30 ... (I)\] multiply second equation with 3, it becomes \[-15x-6y=-42 .... (II)\] add \[I + II\] we have \[24y=-72 \implies y=-3\] put value of y in any of the equation to get the value of x. it comes out to be 4.
solution is (4, -3)
thankss
your welcome. did you get it?
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cant we times -5x-2y=-1 by 3 ??
for cross check you can put x=4 and y=-3 in original equation .. it must satisfy.
I guess equation is \[-5x-2y=-14\]
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