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Find the solutions of the equation Cos2(theta)=3Cos(theta)-2 that are in the interval [0,2pi)
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is it \[\cos 2 \theta or \cos^2\theta\]
cos^2 -3cos +2=0 c0s^2 -2cos -cos+2=0 cos(cos-2)-1(cos-2)=0 (cos-1)(cos-2)=0
cos=2 not possible as it give max value =1
cos theta =1
it give value =1 at 0 and 2pi
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