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three particles of same mass m are fixed to a uniform cirular loop of mass M and radius r at the corners of an equilateral triangle.The loop is free to move in a vertical plane about a point on its circumference lying opposite to any one of the masses m.The length of equivelnt simple pendulum is
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holymoly.. can you draw this? xD
|dw:1395234316412:dw| @Mashy
yea i was hoping.. if she could draw that :P..
First can you find the centre of mass?
@samigupta8 if you really want help then respond what @mashy and @AravindG asked.
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but i m unable to see half of the screen in my computer
|dw:1395238794370:dw| \[\tau=I \alpha \] you know torque u can calculate I about axis of rotation
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