Question

Please help! Given the equation 2Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.

x = 6, solution is not extraneous

x = 6, solution is extraneous

x = 11, solution is not extraneous

x = 11, solution is extraneous

Answer 1

sqrt(x-5) or sqrt(x) -5?

Answer 2

@lucaz that isn't an answer

Answer 3

2 square root of x-5=2

Answer 4

use paranthesis for the radical, it will give different answers