Question

Ella's college professors assign homework independently from each other. Ella knows that there is a 60% chance that she will have math homework tonight and a 70% chance that she will have English homework. What is the probability that she will NOT have math or English homework tonight? 10% 12% 42% 70%

Answer 1

This looks really easy.. I don't know what I'm not understanding!

Answer 2

let A=have math home work
B=event have English home work.
\[P(A)=\frac{ 60 }{100 }=0.6,P(\not A)=1-.06=0.4\]
find P(not B)
Then P(not A or not B)=P(not A )*p(not B)