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how do i solve √5-9 / √5-3 ?
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\[\frac{ \sqrt{5}-9 }{ \sqrt{5}-3 }\] Rationalise the denominator.
what do you mean @surjithayer
\[\frac{ \sqrt{5}-9 }{\sqrt{5}-3 }\times \frac{ \sqrt{5}+3 }{\sqrt{5}+3 }=\frac{ 5+3\sqrt{5}-9\sqrt{5}-27 }{5-3^2 }=\frac{ -22-6\sqrt{5} }{ 5-9 } =?\]
and at the end how do you solve to get the answer?
\[=\frac{ -2\left( 11+3\sqrt{5} \right) }{-4 }=\frac{ 11 }{2 }+\frac{ 3\sqrt{5} }{ 2 }\]
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okay, hmm i think i get it..
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