Question

solve: (6x-4)^1-4 = (5+3x)^ 1/4

Answer 1

(6*x-4)^1-4 = ((3*x+5)^1)/4 // - ((3*x+5)^1)/4

(6*x-4)^1-(((3*x+5)^1)/4)-4 = 0

6*x-((3*x+5)/4)-4-4 = 0

(-1*(3*x+5))/4+6*x-4-4 = 0

(-1*(3*x+5))/4+(4*6*x)/4+(-4*4)/4+(-4*4)/4 = 0

4*6*x-1*(3*x+5)-4*4-4*4 = 0

21*x-16-16-5 = 0

21*x-21-16 = 0

21*x-37 = 0

(21*x-37)/4 = 0

(21*x-37)/4 = 0 // * 4

21*x-37 = 0

21*x-37 = 0 // + 37

21*x = 37 // : 21

x = 37/21

x = 37/21