Ms. Millie showed the graphs of the functions y=log2x and y=log4x to her students. Which conclusion is incorrect?
A. The x-intercept of each graph is 0
B. The graphs never intersect the y-axis
C. The domain of each function is {x:x>0}
D. The range of each function is {y: all real numbers}
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OpenStudy (anonymous):
I am not quite sure, but I think it is the letter B?
OpenStudy (jdoe0001):
graph them, look at them
OpenStudy (anonymous):
okay, by definition, what is log(a)?
OpenStudy (anonymous):
I don't know how to put the 4 in TL-84 calculator
OpenStudy (anonymous):
Log is a power
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OpenStudy (anonymous):
log(a)=x is the solution to the equation e^(x)=a.
OpenStudy (anonymous):
is e you mean lnx?
OpenStudy (anonymous):
e is exponential.
OpenStudy (anonymous):
Oh, okay...
OpenStudy (anonymous):
So if you substitute in your question x=0, you get log0. What is log 0?
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OpenStudy (anonymous):
e^o=1
OpenStudy (anonymous):
um, i have confused you a little bit, the two x's are different.
OpenStudy (anonymous):
in your problem you're looking for
log x=a
log 0=a
e^(which power)=0
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
okay, so it should be clear that there is no power of e that will give you 0. So the answer to your question is A.
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OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
I'm more concerned about you understanding it, than getting the answer. Is everything clear?