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is answer A ?
answer is c. surely.
\[\int\limits\limits Fdt = \Delta P = m(v_{2}-v _{1})\] \[\int\limits Fdt =\] area under F-t graph = 4 \[4 = 1 (v _{2}-1) \implies v _{2} = 5\]
What does \[\Delta P\] mean? Also, what is the point of having \[\int\limits_{?}^{?} F \]?
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\[\Delta P =\] change in momentum.
its a formula derived by newtons laws of motion.
Ok thanks, I'll look them up for more information
refer any textbook with topic as 'impulse'
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