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Physics 20 Online
OpenStudy (anonymous):

I'll give a medal for your help!

OpenStudy (anonymous):

OpenStudy (anonymous):

is answer A ?

OpenStudy (anonymous):

answer is c. surely.

OpenStudy (anonymous):

\[\int\limits\limits Fdt = \Delta P = m(v_{2}-v _{1})\] \[\int\limits Fdt =\] area under F-t graph = 4 \[4 = 1 (v _{2}-1) \implies v _{2} = 5\]

OpenStudy (anonymous):

What does \[\Delta P\] mean? Also, what is the point of having \[\int\limits_{?}^{?} F \]?

OpenStudy (anonymous):

\[\Delta P =\] change in momentum.

OpenStudy (anonymous):

its a formula derived by newtons laws of motion.

OpenStudy (anonymous):

Ok thanks, I'll look them up for more information

OpenStudy (anonymous):

refer any textbook with topic as 'impulse'

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