Question

sin^2xcosx=cosx

Answer 1

\(\bf sin^2(x)cos(x)=cos(x)\implies sin^2(x)=\cfrac{cos(x)}{cos(x)}\implies sin^2(x)=1
\\ \quad \\
\sqrt{sin^2(x)}=\pm\sqrt{1}\implies sin(x)=\pm1
\\ \quad \\
\implies sin^{-1}[sin(x)]=sin^{-1}(\pm 1)\implies x=sin^{-1}(\pm 1)\)